Specific heat Converter
Result:
1 joule per kilogram-kelvin (j/(kg⋅k)) = 1 joule per kilogram-celsius (j/(kg⋅°c))
Popular Specific-heat Conversions
- joule per kilogram-kelvin to calorie per gram-celsius
- btu per pound-fahrenheit to joule per kilogram-kelvin
Complete List of Specific-heat Units
All available specific-heat units for conversion:
- joule per kilogram-kelvin [J/(kg⋅K)]
- 1 joule per kilogram-celsius [J/(kg⋅°C)] = 1 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 calorie per gram-celsius [cal/(g⋅°C)] = 4184 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 kilocalorie per kilogram-celsius [kcal/(kg⋅°C)] = 4184 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 BTU per pound-fahrenheit [BTU/(lb⋅°F)] = 4186800 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 kilojoule per kilogram-kelvin [kJ/(kg⋅K)] = 1000 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 joule per gram-kelvin [J/(g⋅K)] = 1000 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 watt-hour per kilogram-kelvin [Wh/(kg⋅K)] = 3600 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 calorie per gram-kelvin [cal/(g⋅K)] = 4184 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 joule per kilogram-kelvin [J/(kg⋅K)] = 10000 erg per gram-kelvin [erg/(g⋅K)]
- 1 foot-pound per pound-fahrenheit [ft⋅lbf/(lb⋅°F)] = 2.9891111 joule per kilogram-kelvin [J/(kg⋅K)]
- 1 BTU per slug-fahrenheit [BTU/(slug⋅°F)] = 13499.281 joule per kilogram-kelvin [J/(kg⋅K)]