Convert joule to foot-pound

Enter the value to convert from joule to foot-pound.

J
foot-pound
Result: 25 joules (j) = 18.4390537092 foot-pounds (ft⋅lbf)

How to Convert Joule to Foot-pound

Converting joule to foot-pound is straightforward using our conversion calculator.

Conversion Formula

ft⋅lbf = J ÷ 1.35581795

Reverse conversion: Convert foot-pound to joule

Comparison: Joule vs Foot-pound

When to Use Each Unit

Joule: Universal scientific unit for all forms of energy: mechanical, electrical, thermal, chemical, and nuclear energy worldwide.

Foot-pound: Used in United States for mechanical work, torque specifications, ballistics, and engineering calculations.

Common Conversion Values

  • 1000 J = 1 kJ
  • 1 J ≈ 0.239 cal
  • 3,600,000 J = 1 kWh
  • 1 J ≈ 0.738 ft⋅lbf

About Joule

Definition: The joule (symbol: J) is the SI unit of energy, equal to the energy expended when applying one newton of force through one meter of distance.

History: Named after English physicist James Prescott Joule in 1889. Established the mechanical equivalent of heat and energy conservation.

Current Use: Universal scientific unit for all forms of energy: mechanical, electrical, thermal, chemical, and nuclear energy worldwide.

Examples: Apple: 350,000 J, car battery: 4.3 MJ, lightning bolt: 1-5 billion J, human daily intake: 8-10 MJ

About Foot-pound

Definition: The foot-pound (symbol: ft⋅lbf) is the energy expended when applying one pound-force through one foot of distance.

History: Imperial unit derived from mechanical work measurements. Standard for engineering applications in imperial system.

Current Use: Used in United States for mechanical work, torque specifications, ballistics, and engineering calculations.

Examples: Bullet energy: 1000-4000 ft⋅lbf, bow arrow: 50-100 ft⋅lbf, hammer blow: 25 ft⋅lbf, car engine: 300,000 ft⋅lbf

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